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The volume of oxygen liberated at STP from 15 mL of 20 volume `H_(2)O_(2)` isA. 100 mLB. 150 mLC. 200 mLD. 300 mL |
Answer» Correct Answer - D 1 mL of 20 volume `H_(2)O_(2)` liberates `O_(2)` at STP =20 mL `therefore ` 15 mL of `H_(2)O_(2)` will liberate `O_(2)` at STP `=15xx20=300 `mL |
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