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The volume of oxygen liberated from `15 ml` of 20 volume `H_(2)O_(2)` isA. `250 ml`B. `300 ml`C. `150 ml`D. `200 ml` |
Answer» Correct Answer - B Quantity of `H_(2)O_(2)=15 ml` and volume of `H_(2)O_(2)=20`. We know that 20 volume of `H_(2)O_(2)` means 1 litre of this solutin will give 20 litres of oxygen at `N.T.P.` Since, oxygen liverated from `1000 ml(1` litres `)` of `H_(2)O_(2)=20` litres, therefore oxygen liberate from `15 ml` of `H_(2)O_(2)=(20)/(1000)xx15=0.3`litre `=300ml`. |
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