1.

The volume of SO_2produced at S.T.P. by the combustion of 50 g of sulphur containing 4% sand by weight will be

Answer»

33.6 L
22.4L
11.2 L
44.8 L

Solution :Amount of SAND `= (50 xx 4)/(100) = 2g`
Amount of sulphur = 50 - 2 = 48 G
`underset(32g)(S) + O_2 to underset(22.4L)(SO_2)`
32g of sulphur at S.T.P. GIVE `SO_2` = 22.4 L
48 g of sulphur at S.T.P.Give `SO_2`
` = (22.4)/(32) xx 48 = 33.6`


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