The volume of the air bubble increases by 10% when it rises from bottom to the surface of a water pond. If the temperature of the water is constant, find the depth of the pond.

The volume of the air bubble increases by 10% when it rises from botto

1.	The volume of the air bubble increases by 10% when it rises from bottom to the surface of a water pond. If the temperature of the water is constant, find the depth of the pond.
Answer» Solution :Volume of the AIR bubble at the bottom of the pond `(V_(1))=V` Volume of the air bubble at the surface of the pond `V_(2)=V times 110/100` Pressure at the bottom of the pond `(P_(1))=(h+H)` of water column where .h. is the DEPTH of the pond and .H. is the atmospheric pressure (on water BAROMETER) Pressure on the surface of the pond `(P_(2))=H` cm of water column From Boyle.s law, `P_(1)V_(1)=P_(2)V_(2)` (or) `(h+H)V=H(V times 110/100) rArr h+H=H times110/100 rArr h=H times 110/100-H=H times 10/100=H/10` `therefore` Depth of the bond = H/10.