1.

The volume of the tetrahedron formed by the coterminous edges veca, vecb, vec c is 3. Then the volume of the parallelopiped formed by the coterminous edges veca+vecb, vecb+vec c, vec c+ veca is

Answer»

36
34
32
30

Solution :`(1)/(6)[VECA vecb vec C]=3` (GIVEN)
`[veca vecb vec c]=18`
`"VOL. of parallelopiped"=[veca+vecb""vecb+vec c""vec c + a]`
`=2[veca vecb vec c]=2xx18=36`


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