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The volume of water flowing out through a pipe in a given time is V = KA^2ut, where A is the area of cross-section of the pipe, u is the speed of the flow, t is the time and K is a dimensionless constant. Check the correctness of the equation. |
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Answer» SOLUTION :V = `KA^2ut` [LHS] - `[L^3]` [LHS] = `[L^2][LT^-1][T]` = `[L^5]` [LHS] `ne` [RHS], the EQUATION is wrong. |
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