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The volume of water needed to dissolve 1g of BaSO_4 (K_(sp)=1.1 xx 10^(-10)) at 25^(@) Cis { M. W of BaSO_4 is 233} |
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Answer» 820 L ` 1 gm =(1)/(233)` moles ` therefore ` Volume of water ` = (1//233)/( 10 ^(-5))= 430 L` |
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