1.

The volume of water to be added N/2 HCl to prepare 500cm^(3) of (N)/(10) solution is

Answer»

`450cm^(3)`
`100cm^(3)`
`45cm^(3)`
`400cm^(3)`

Solution :As `N_(1)V_(1)=N_(2)V_(2)`
`(N)/(2)XXV=(N)/(10)xx500`
V=100 `cm^(3)`
From 100ml of `(N)/(2)HCl` to 500 ml `(N)/(10)HCl`
WATER added=500-100=400ml.


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