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The volume of water to be added to `100 cm^(3)` of 0.5 `NH_(2)SO_(4)` to get decinormal concentration isA. `400 cm^(3)`B. `500 cm^(3)`C. `450 cm^(3)`D. `100 cm^(3)` |
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Answer» Correct Answer - A `100xx0.5 = V_(2)xx(1)/(10)` or `V_(2) = 10xx100xx0.5=500cm^(3)` |
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