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The volume of water to be added to 100 mL of 0.5N H_(2)SO_(4) acid solution to get solution of decinormal concentration is : |
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Answer» 400 mL `(0.5 N)xx(100mL)=(0.1 N)xxV_(2)` `V_(2)=((0.5N)xx(100mL))/((0.1N))=500mL` Volume of water to be added=(500-100)=400 mL |
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