The volume of water to be added to 100cm^(3) of 0.5 N H_(2)SO_(4) to get decinormal concentration, is

The volume of water to be added to 100cm^(3) of 0.5 N H_(2)SO_(4) to g

1.	The volume of water to be added to 100cm^(3) of 0.5 N H_(2)SO_(4) to get decinormal concentration, is
Answer» 100 `cm^(3)` `450cm^(3)` `500cm^(3)` `400CM^(3)` Solution :`N_(1)V_(1)=N_(2)V_(2)` i.e.`0.5xx100=0.1xxV_(2)orV_(2)=500cm^(3)` `therefore` WATER to be added to `100CM^(3)` solution `= 500-100=400cm^(3)`