1.

The volume of0.0168 mol of O_(2) obtained by decomposition of KClO_(3) and collected by dispfacement of water is 428 mL at a pressure of754 mm Hg at 25 °C. The pressure of water vapour at 25 °C is

Answer»

18 MM Hg
20 mm Hg
22 mm Hg
24 mm Hg

Solution :VOLUME of 0.0168 moles at STP
`=0.0168xx22400=376.3` ML.
`(P_(1)V_(1))/(T_(1))=(P_(2)V_(2))/(T_(2))` or `(760xx376.3)/273=(P_(2)xx428)/298` or `P_(2)=730mm`
Pressure of water= 754 - 730=24 mm


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