1.

The volume strength of `1*5` N `H_(2)O_(2)` solution isA. `4*8`B. `5*2`C. `8*8`D. `8*4`.

Answer» Correct Answer - D
Strength = Normality `xxEq. Mass = 1*5xx17=25*5g L^(-1)`
`{:(" "2H_(2)O_(2),to,2H_(2)O,+,O_(2)),(" "68g,,,,22400mL.),(~~68mL,,,,):}`
60 g of `H_(2)O_(2)` on decomposition gives `O_(2)=22400 mL`
`25*5` g of `H_(2)O_(2)` on decomposition gives `O_(2)=(22400xx25.5)/(68)=8400mL`
`:.` 1000 mL of `H_(2)O_(2)` solution gives 8400 mL of `O_(2)`
1 mL of `H_(2)O_(2)` solution gives 8*4 mL of `O_(2)`. ltbrlt `:.` Vol. strength of `H_(2)O_(2)=8*4`


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