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The volume strength of `1.5 N H_2O_2` solution isA. `4.8`B. `5.2`C. `8.8`D. `8.4` |
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Answer» Correct Answer - D Strength =Normality `xxEW` of `H_(2)O_(2)` `=1.5 Nxx1.7 g L^(-1)=25.5 g L^(-1)` `underset(68g)(2H_(2)O_(2))to2H_(2)O+underset(22400 mL "at STP")(O_(2))` 68 g of `H_(2)O gives=22400` mL of `O_(2)`at STP `25.5 g H_(2)O_(2)` gives =`22400/68xx25.5 =8400` mL of `O_(2)` at `STP` `25.5 g` of `H_(2)O_(2) ` is present in `1000 m L` of `H_(2)O_(2)` solution `1000` mL of `H_(2)O_(2)` gives 8400 mL of `O_(2)`at STP 1mL of `H_(2)O_(2)` gives `8400/1000` mL of `O_(2)` at `STP` `=8.4 mL` of `O_(2)` Hence, volume strength of `1.5 N H_(2)O_(2)=8.4` volume. Or mass of `H_(2)O_(2)` in `1.5 N` solution `=EW` of `H_(2)O_(2)xx1.5 N` `=17xx1.5=25.5 g//L` Hence, volume strength of `1.5 N H_(2)O_(2)` solution `=(22.4xx25.5)/68=8.4` |
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