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The volume strength of 1.54 N H_(2)O_(2) solution is: |
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Answer» 4.8L `=(1.5"equiv" L^(-1))xx(17"equiv"^(-1))` `underset(68g)(2H_(2)O_(2)) to underset(22.4L)(2H_(2)O+O_(2))` 68g of `H_(2)O_(2)` evolve `O_(2)` under N.T.P conditions=22.4L 25.5g of `H_(2)O_(2)` evolve `O_(2)` under N.T.P conditions `=((22.4L)xx(25.5g))/(68g)=8.4L` |
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