1.

The volume to be excluded due to only two molecules of a gas in collision with a fixed point of impact is (0.09)/(N_A) litre (NA = Avogadro number). If the value of 'a' is 3.6 atm L^2 mol^(-2) then the value of Boyle's temperature is, 10^x K. What is the value of 'x'? (R = 0.08 L atm K^(-1)m^(-1))

Answer»

SOLUTION :`B = (0.09)/2 " litre mol"^(-1) implies T_b = a/(bR) = (3.6)/((0.09)/2 R)`
`= (7.2)/(0.09 xx 0.08) = (72000)/(9 xx 8) = 1000 K`.


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