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The volume (V) of a monoatomic gas varies with its temperature (T), as shown in the graph. The ratio of work done by the gas, to the heat absorbed by it, when it undergoes a change from state A to state B, is ____ |
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Answer» `2/7` In isobaric PROCESS `W=PDeltaV=muR DeltaT` ….(1) `DeltaQ=mu C_P DeltaT`…(2) For monatomic GAS MOLECULE f=3 `therefore C_P=f/2 R +R =5/2 R` …(3) `[because f=3]` `therefore W/(DeltaQ)=(muR DeltaT)/(mu C_P DeltaT)` [From equ. (1) and (2)] `therefore W/(DeltaQ)=R/C_P=R/(5/2R)` [From equ. (3)] `therefore W/(DeltaQ)=2/5` |
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