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The water level in a metric measuring cup is 0.75 L before the addition of a pebble weighting 150 g. The water level after submerging the pebble is 0.82 L Determine the density of the pebble. |
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Answer» Volume displaced by the pebble = 0.82 – 0.75 = 0.07 L = 70 mL Mass of the pebble = 150 g \(\therefore\) Density of pebble = \(\frac{Mass}{Volume}\) = \(\frac{150}{70}\) = 2.14 g mL-1 |
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