1.

The wave number of the shortest wavelength of absorption specturm of H-atom is (Rydberg constant =109700cm^(-1))

Answer»

`109700 CM^(-1)`
`3//4xx109700cm^(-1)`
`1//2xx109700cm^(-1)`
`9//10xx109700cm^(-1)`

Solution :The SHORTEST wavelength correspondsto MAXIMUM energy `:.n_(2)=oo`
`barv=109700cm^(-1)1/(1^(2))-1/(oo^(2))=109700cm^(-1)`


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