the wavelength limit present in the pfund series is `(R=1-097xx10^7m^- – InterviewSolution

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1.	the wavelength limit present in the pfund series is `(R=1-097xx10^7m^-1)`A. 1572 nmB. 1898 nmC. 2278 nmD. 2535 nm
Answer» Correct Answer - C The wavelength for Pfund series is given by `(1)/(lambda)=R[1/(5^2)-1/(n^2)]` for series limit, `n=prop` therefore lambda `=(25)/(R)=(25)/(1.097xx10^7)=2278nm`.

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