The wavelength of a certain line in Balmer Series is observed to be 4329 Å. To what value of .n. does this correspond ? (R_(H) = 109678cm^(-1)) (Z=1)

The wavelength of a certain line in Balmer Series is observed to be 43

1.	The wavelength of a certain line in Balmer Series is observed to be 4329 Å. To what value of .n. does this correspond ? (R_(H) = 109678cm^(-1)) (Z=1)
Answer» Solution :`1/(lambda) = R_H Z^2 [1/(n_1^2) - 1/(n_2^2)]` `implies1/(4329xx10^(-8)) = 1.09678 XX 10^5 [1/4 - 1/(n_2^2)]` `THEREFORE n_2 = 5`