InterviewSolution
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InterviewSolution
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The wavelength of first line of Balmer series is `6563Å`. The wavelength of first line of Lyman series will beA. `1215.4Å`B. `2500Å`C. `7500Å`D. `600Å` |
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Answer» Correct Answer - A `(lambda_("Lyman"))/(lambda_("Blamer"))=(((1)/2^(2)-(1)/(3^(2))))/(((1)/(1^(2))-(1)/(2^(2))))=(5)/(27)" " [:. (1)/(lambda)=R((1)/(n_(f)^(2))-(1)/(n_(i)^(2)))]` `rArrlambda_("Lyman")=(5)/(27)xxlambda_("Balmer")=(5)/(27)xx6563=1215.4Å` |
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