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The wavelength of `K_alpha` X-ray of tungsten is `21.3` pm. It takes `11.3` keV to knock out an electron from the L shell of a tungsten atom. What shoulb be the minimum accelerating voltage across an X-ray tube having trungsten target which allows production of `K_alpha` X-ray? |
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Answer» `E_(K)-E_(L)=(hc)/lambda_(K_(alpha))` `lambda_(K_(alpha))=21.3 pm=0.0213 nm` `E(eV)=1242/(lambda(nm))=1242/0.0213=58.3 ke V` `E_(K)-E_(L)=E` `E_(K)-11.3=58.3` `E_(K)=69.6 ke V` Acceleration potential `=69.6 kV` |
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