InterviewSolution
Saved Bookmarks
| 1. |
The wavelength of spectral line coming from a distant star shifts from 600 nm to 600.1 nm. The velocity of the star relative to earth isA. 50 km `s^(-1)`B. 100 km `s^(-1)`C. 25 km `s^(-1)`D. 200 km `s^(-1)` |
|
Answer» Correct Answer - A Here, `lambda = 600 nm` `triangle lambda=600.1 nm - 600nm=0.1 nm` As `(v_(s))/(c)= (triangle lambda)/(lambda) , :. (triangle lambda)/(lambda)c=(0.1nm)/(600nm)xx3xx10^(8)ms^(-1)` ` :.v_(s)=50xx10^(3)ms^(-1)=50kms^(-1)` |
|