The wavelength of the electron emitted, when in a hydrogen atom, electron falls from infinity to stationary state 1, would be (Rydberg constant = 1.097 xx 10^(7) m^(-1))

The wavelength of the electron emitted, when in a hydrogen atom, elect

1.	The wavelength of the electron emitted, when in a hydrogen atom, electron falls from infinity to stationary state 1, would be (Rydberg constant = 1.097 xx 10^(7) m^(-1))
Answer» 91 nm 192 nm 406 nm `9.1 xx 10^(-8) nm` SOLUTION :`bar(v) = (1)/(lamda) = R ((1)/(n_(1)^(2)) - (1)/(n_(2)^(2)))` `= 1.097 xx 10^(7) m^(-1) ((1)/(1^(2)) - (1)/(OO^(2)))` `= 1.097 xx 10^(7) m^(-1)` or `lamda = (1)/(1.097 xx 10^(7)) m = 0.91 xx 10^(-7) m = 91 nm`