The wavelength of the first member of theBalmer series in hydrogen spectrum is xÅ. Then the wave length ("in "Å) of the first member of Lyman series in the same spectrum

The wavelength of the first member of theBalmer series in hydrogen spe

1.	The wavelength of the first member of theBalmer series in hydrogen spectrum is xÅ. Then the wave length ("in "Å) of the first member of Lyman series in the same spectrum
Answer» `(5)/(27) x ` `4/3 x ` `(27)/(5) x ` `(5)/(36)` x SOLUTION :For Lyman SERIES `1/(lambda) = bar(upsilon_2) = R(1/((1)^2) - 1/((2)^2))` For Balmer series , `bar(upsilon_1) = R (1/((1)^2) - 1/((3)^2))`