The wavelength of two sine waves are lambda_(1) = 1 m and lambda_(2) = 6 m . Calculate the corresponding wave numbers .

The wavelength of two sine waves are lambda_(1) = 1 m and lambda_(2) =

1.	The wavelength of two sine waves are lambda_(1) = 1 m and lambda_(2) = 6 m . Calculate the corresponding wave numbers .
Answer» <html><body><p>`1.05radm^(-1)and 6.28rad m^(-1)`<br/>`6.28radm^(-1)and 1.05radm6(-1)` <br/>`1radm ^(-1)and0.1666rad m^(-1)`<br/>`0.166radm^(-1)and <a href="https://interviewquestions.tuteehub.com/tag/rad-1175618" style="font-weight:bold;" target="_blank" title="Click to know more about RAD">RAD</a> m^(-1)`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> : Standard <a href="https://interviewquestions.tuteehub.com/tag/wave-22399" style="font-weight:bold;" target="_blank" title="Click to know more about WAVE">WAVE</a> equation, ` Y=Asin( <a href="https://interviewquestions.tuteehub.com/tag/kx-1064991" style="font-weight:bold;" target="_blank" title="Click to know more about KX">KX</a> - omegat)` <br/> ` K_1= ( 2pi )/( lamda_1) = ( 2pi )/( 1) = 6.28rad m^(-1)` <br/> ` K_2 =(2pi )/( lamda_2) =(2pi )/( 6 )=1.05rad m^(-1)`</body></html>