The wavelength of two sine waves are lambda_(1) = 1 m and lambda_(2) = 6 m . Calculate the corresponding wave numbers .

The wavelength of two sine waves are lambda_(1) = 1 m and lambda_(2) =

1.	The wavelength of two sine waves are lambda_(1) = 1 m and lambda_(2) = 6 m . Calculate the corresponding wave numbers .
Answer» `1.05radm^(-1)and 6.28rad m^(-1)` `6.28radm^(-1)and 1.05radm6(-1)` `1radm ^(-1)and0.1666rad m^(-1)` `0.166radm^(-1)and RAD m^(-1)` SOLUTION : Standard WAVE equation, ` Y=Asin( KX - omegat)` ` K_1= ( 2pi )/( lamda_1) = ( 2pi )/( 1) = 6.28rad m^(-1)` ` K_2 =(2pi )/( lamda_2) =(2pi )/( 6 )=1.05rad m^(-1)`