The wavelength of two sound notes in air are (40)/(195)m and (40)/(193)m. Each note produces 9 beats per second, separately with a third note of fixed frequency. The velocity of sound in air in m//s is

The wavelength of two sound notes in air are (40)/(195)m and (40)/(193

1.	The wavelength of two sound notes in air are (40)/(195)m and (40)/(193)m. Each note produces 9 beats per second, separately with a third note of fixed frequency. The velocity of sound in air in m//s is
Answer» 360 320 300 340 Solution :`(lambda_(1))/(lambda_(2))=(n_(2))/(n_(1))=(40//193)/(40//195)=(195)/(193)` `impliesn_(2) gt n_(3) gt n_(1)impliesn_(2)-n_(3)=9`...........`(1)` `n_(3)-n_(1)=9`............`(2)` `(1)+(2)impliesn_(2)-n_(1)=18`