1.

The wavelength range of the visible spectrum extends from violet (400 nm) to red (750 nm). Express these wavelengths in frequencies (Hz) (1 nm = 10^(-9)m)

Answer»

Solution :WAVELENGTH of violet radiation `= 400NM = 400 xx 10^(-9) m`
`:.` Frequency `(v) = (c)/(lamda) = (3 xx 10^(8) ms^(-1))/(400 xx 10^(-9) m) = 7.5 xx 10^(14) s^(-1) or 7.5 xx 10^(14)HZ`
Wavelength of RED radiation `= 750nm = 750 xx 10^(-9)m`
`:.` Frequency `(v) = (c)/(lamda) = (3 xx 10^(8) ms^(-1))/(750 xx 10^(-9)m) = 4.00 xx 10^(14) s^(-1) or 4.00 xx 10^(14)Hz`
Thus, in terms of frequency, the range of the visible lights is from `4.0 xx 10^(14) Hz " to " 7.5 xx 10^(14)Hz`


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