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The wavenumber of the first line in the Balmer series of hydrogen is 15200 cm^(-1).What is the wavenumber of the first line in the Balmer series of Be^(3+) ? |
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Answer» Solution :`(1/lamda)_(Be^(3+)) = z^2 (1/lamda)_H` `2.43 xx 10^5 CM^(-1)` |
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