1.

The wedge_(m)^(@) values for NaCl and KCl are 126.5 and 149.9Omega^(-1)cm^(2)mol^(-1) respectively. The ionic conductances of Na^(+) at infinite dilution is 50.1 Omega^(-1)cm^(2)mol^(-1). Calculate the ionic conductance at infinite dilution for K^(+) ion.

Answer»


SOLUTION :`wedge_(m)^(@)(KCL)-lamda_(m)^(@)(NaCl)=lamda_(K^(+))^(@)-lamda_(NA^(+))^(@)=149.9-126.5=23.4Omega^(-1)cm^(2)mol^(-1)`
`lamda_(K^(+))^(@)=23.4+lamda_(Na^(+))^(@)=23.4+50.1=73.5Omega^(-1)cm^(2)mol^(-1)`.


Discussion

No Comment Found

Related InterviewSolutions