The weight of 1 molecule of the compoundC_(60)H_(122)is...(N_(A)=6.0xx

1.	The weight of 1 molecule of the compoundC_(60)H_(122)is...(N_(A)=6.0xx10^(23))
Answer» `1.4xx10^(-21)g` `1.09xx10^(-21)g` `5.025xx10^(23)g` `16.023xx10^(23)g` Solution :Molecular weight of `C_(60)H_(122)=12xx60+122xx1` `=720+122=842` `:.6xx10^(23)` molecule `C_(60)H_(122)` hasmass `= 842g` `:.1` molecule of `C_(60)H_(122)` has mass `= (842)/(6xx10^(23))` `=140.333xx10^(-23)g=1.4xx10^(-21)g`

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