1.

The weight of `1 xx 10^(22)` molecules of `CuSO_(4). 5H_(2)O` is

Answer» Correct Answer - `4.14g`
Molar mass of `CuSO_(4).5H_(2)O`
`= 63.5 + 32+4 xx 16 + 5 xx 18 = 249.5 g`
Also, molar mass represents mass of Avogadro number of molecules in gram unit, therefore
`because 6.023 xx 10^(23)` molecules of `CuSO_(4).5H_(2)O` weigh `249.5 g`
`:. 10^(22)` molecules will weigh `(249.5)/(6.023 xx 10^(23)) xx 10^(22) = 4.14 g`


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