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The weight of `1 xx 10^(22)` molecules of `CuSO_(4). 5H_(2)O` is |
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Answer» Correct Answer - `4.14g` Molar mass of `CuSO_(4).5H_(2)O` `= 63.5 + 32+4 xx 16 + 5 xx 18 = 249.5 g` Also, molar mass represents mass of Avogadro number of molecules in gram unit, therefore `because 6.023 xx 10^(23)` molecules of `CuSO_(4).5H_(2)O` weigh `249.5 g` `:. 10^(22)` molecules will weigh `(249.5)/(6.023 xx 10^(23)) xx 10^(22) = 4.14 g` |
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