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The weight of 112 m L of oxgen at NTP isA. `0.64g`B. `0.96g`C. `0.32g`D. `0.16g` |
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Answer» Correct Answer - D `22400mL of O_2` at NTP occupied by `=32g O_2` `therefore 112mL of O_2` at NTP occupied by `=(32)/(22400)xx112gO_2=0.16gO_2` Hence , the weight of `112mL` of oxygen at NTP is `0.16g`. |
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