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The weight of 350 ml a diatomic gas at `0^(@)C` and 2atm pressure is 1 gm.The weight of one atom is :-A. `(16)/(N_(A))`B. `(32)/(N_(A))`C. `16N_(A)`D. `32N_(A)` |
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Answer» Correct Answer - A PV = nRT ` (2xx350)/(1000) = (1)/(Mw)xx0.082xx273` Mw = 32 wt of molecule of diatomic molecule `A_(2) = (32)/(N_(A))` wt of 1 atom of diatomic molecule ` A_(2) = (32)/(N_(A))xx(1)/(2)=(16)/(N_(A))` |
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