The weight of AgCl precipitated when a solution containing 5.85 g of NaCl is added to a solution containing 3.4g of AgNO_3 is

The weight of AgCl precipitated when a solution containing 5.85 g of N

1.	The weight of AgCl precipitated when a solution containing 5.85 g of NaCl is added to a solution containing 3.4g of AgNO_3 is
Answer» 28g 9.25g 2.870g 58g Solution :`AgNO_3+NACL to AGCL + NaNO_3` No. of moles of `AgNO_3=(3.4)/(170)=0.02` No. of moles of NaCl `=(5.85)/(58.5)=0.1` limiting REAGENT = `AgNO_3` 1 mole of `AgNO_3` produces 1 mole of AgCl 0.02 mole of `AgCO_3` produce 0.02 mole of AgCl Weight of AgCl produced = `0.02xx143.5=2.870 G`