1.

The weight of chlorine that would be deposited from molten NaCl in one minute by current of 300 milliamperes is

Answer»

`1.123 xx 10^(20)`
`6.621 xx 10^(-3)`
`2.216 xx 10^(20)`
`5.6 xx 10^(19)`

Solution :Weight of chlorine deposited may be calculated ACCORDING to FARADAY's first law of electrolysis .
`W = (ixx t xx E)/(96500)therefore t = 300 m A = 300 xx 10^(-3) A`
`= (300 xx 10^(-3) xx 60 xx 35.5)/(96500) ` (t = 1 min = 60 SEC)
`= 6.621 xx 10^(-3)` GMS (E of Cl = `("At. mass")/(1) = 35.5)`


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