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The weight of one molecule of a compound `C_(60)H_(12)` isA. `1.3xx10^(-20)`gB. `5.01xx10^(-21)`gC. `3.72xx10^(23)`gD. `1.4xx10^(-21)`g |
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Answer» Correct Answer - D Wt. of one molecule `= ("Mol mass of" C_(60)H_(122))/(6.023xx10^(23))` `= ((12xx60)+122)/(6.023xx10^(23)) = (842)/(6.023xx10^(-23))` `=1.4xx10^(-21)g` |
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