The weight of pure NaOH required to prepare 250 mL of 0.1 N solution i

1.	The weight of pure NaOH required to prepare 250 mL of 0.1 N solution is :
Answer» 4 g 2 g 1 g 5 g Solution :`("0.1 EQUIV. L"^(-1))=("Mass of NaOH")/(("40 g equiv")^(-1)xx("0.2 5L"))` Mass of `NaOH = 0.1 xx 40 xx 0.25 =1g`.

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