1.

The weight of sodium carbonate required to prepare 500 ml of a semi-normal solution isA. 13.25 gB. 26.5 gC. 53 gD. 6.125 g

Answer» Correct Answer - A
`N=(w xx1000)/(eq.wt. xx " volume in ml.")eq.wt.=(106)/(2)=53`
`w=(0.5xx53xx500)/(1000)=13.25`.


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