1.

The weight percentage of iron in heamo-globin is 0.33. If the approximate molecular weight of heamoglobin is 68000, how many iron atoms are present in the molecule? (At.wt. of Fe is 56)

Answer»

SOLUTION :100 parts of HEAMOGLOBIN =0.33 parts iron
6800 parts of heamoglobin=?
WEIGHT of Fe in heamoglobin `=(6800)/(100) xx 1/3 =227g`
56g of Fe =one Fe 227g of Fe=?
Numbewr of iron atoms `=(227)/(56)=4`


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