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The weight ratio of elements carbon, nitrogen and hydrogen in a compound of molecular mass 108 is 18:2:7. What is its molecular formula? |
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Answer» Solution :`C:H:N:=(18)/(12):2/1:7/(14)=3:4:1` Empirical formula is `C_(3)H_(4)N` Empirical formula weight =54 `n=(108)/(54)=2` Molecular formula `=2 XX (C_(3)H_(4)N)=C_(6)H_(8)N_(2)` |
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