1.

the work done against force of friction is

Answer»

8.7 J
10.7 J
7.8 J
12.7 J

Solution :WORK against FRICTION is `W_f=fd=muNd=mumgcosthetad " " (THEREFORE N=mgcos theta)`
`=0.1xx1 kg xx 10 m s^(-2) xx COS 30^@ xx 10 m`
=8.7 J


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