Saved Bookmarks
| 1. |
The work done by a force F=(hati+2hatj+3hatk) N ,to displace a body from positionAto position B is [The position vector of A is r_(1)=(2hati+2hatj+3hatk)m] |
|
Answer» Solution :(a) Work done ,`W=F.(r_(2)-r_(1))` position `r_(2)-r_(1)=hati-hatj+2hatk` `W=(hati+2hatj +3hatk).(hati-hatj+2hatk)=1-2+6=5J` |
|