1.

The work done by a force F=(hati+2hatj+3hatk) N ,to displace a body from positionAto position B is [The position vector of A is r_(1)=(2hati+2hatj+3hatk)m]

Answer»

5 J
3 J
2 J
10 J

Solution :(a) Work done ,`W=F.(r_(2)-r_(1))`
position `r_(2)-r_(1)=hati-hatj+2hatk`
`W=(hati+2hatj +3hatk).(hati-hatj+2hatk)=1-2+6=5J`


Discussion

No Comment Found