The work done by the liberated gas when 55.85 g of iron (molar mass 55.85 g "mol"^(-1)) reacts with hydrochloric acid in an open beaker at 25^@C

The work done by the liberated gas when 55.85 g of iron (molar mass 55

1.	The work done by the liberated gas when 55.85 g of iron (molar mass 55.85 g "mol"^(-1)) reacts with hydrochloric acid in an open beaker at 25^@C
Answer» `-2.48` kJ `-2.22` kJ `+2.22` kJ `+2.48` kJ Solution :`Fe+2HCl + FeCl_2 + H_2` 1 mole of IRON LIBERATES 1 mole of hydrogen gas 55.85 g Iron = 1 mole Iron `therefore` n=1 `T=25^@C`=298 K `w=-PDeltaV` `w=-P((NRT)/P)` w=-nRT w=-1 x 8.314 x 298 J w=-2477.57 J w=-2.48 kJ