1.

The work done during the expansion of a gas from a volume of `4dm^(3)` to `6dm^(3)` against a constant external pressure of 3 atm is (1L atm = 101.32 J)A. `+ 304 J`B. `- 304 J`C. `- 6 J`D. `-608 J`

Answer» Correct Answer - D
`W=-pDeltaV, W=-3xx(6-4)`
`W=-6xx101.32(therefore "1 L atm=101.32 J")`
W=-608 J


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