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The work done in stretching a wire by 0.1 mm is 3 J. Then the work done in stretching another wire of the same material but with double the radius and half the length by 0.1 mm isA. 12 JB. 18 JC. 24 JD. 32 J |
Answer» Correct Answer - C `(W_(2))/(W_(1)) =((1)/(2)F_(2)l)/((1)/(2) F_(1)l)=(F_(2))/(F_(1))=(r_(2)^(2))/(r_(1)^(2)) xx (L_(1))/(L_(2))=4xx2` `W_(2)=8W_(1)` `=8xx3=24J`. |
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