The work function for a metal is 4 eV. To eject the photo electrons with zero velocity the wavelength of the incident light should be

The work function for a metal is 4 eV. To eject the photo electrons wi

1.	The work function for a metal is 4 eV. To eject the photo electrons with zero velocity the wavelength of the incident light should be
Answer» SOLUTION :`(HC)/(LAMBDA) = 1+ phi …. (1) implies3 xx (hc)/(lambda) = 4 + phi ….(2)` On solving `phi = 0.5`