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The work function of Caesium metal is 2.14ev . A beam of light of frequency 6 ×1014 Hz easy incident on metal surface. Find a) energy of incident Photon.b) maximum kinetic energy of photoelectron. Given, h = 6.63 × 10-34 JS |
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Answer» Given, \(\phi=2.14\,ev\) v = 6 x 1014 h = 6.63 x 10-34 55 Js (a) Energy of photon E = hv E = 6.63 x 10-34 x 6 x 1014 E = \(\frac{39.78\times10^{-20}}{1.6\times10^{-19}}\) E = 24.86 x 10-1 E = 2.48 ev (b) Maximum kinetic energy of photo electron k = hv - \(\phi\) k = 2.48 - 2.14 k = 0.34 ev |
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