1.

The work function of nickle is `5eV`. When light of wavelength `2000A^(0)` falls on it, emits photoelectrons in the circuit. The the potential difference necessary to stop the fastest electrons emitted is (given `h=6.67xx10^(-34) Js`)A. `1.0V`B. `1.75V`C. `1.2V`D. `0.75V`

Answer» Correct Answer - C
`V_(0)=(E-omega_(0))/e`


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